what is the output of the following program?
#include<stdio.h>
void main()
{
float x=1.1;
while(x==1.1)
{
printf("\n%f",x);
x=x-0.1;
}
}
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Answer / vikram
No output.Since a float variable is compared with double
constant,condition will not satisfy.
if you don't believe,try your hand on it.
| Is This Answer Correct ? | 30 Yes | 3 No |
Answer / battini.laxman
No output.Loop will not execute atleast once. because
compiler will treat real constant as double. So real
constants will not store exactly equal to that constant
value but appproximately equal to that constan in binary
format. So float value and doule value storing
approximately equal but not exactly.small difference will
be there.so condition will fail at first time.So loop will
not execute atleast once.
| Is This Answer Correct ? | 17 Yes | 0 No |
Answer / shibumon alampatta
First of all we shall look into the binary representation of
decimal number 1.1. It is 1.00011001100110011..... reccuring
infinite fractional part. And in the expression (x == 1.1),
x is a float and 1.1 is double constant. So their precisions
are different and float x = 1.1 and the double constant 1.1
will not be equal. So if we make double x = 1.1, instaed of
float it will work. Also if it is float x = 1.5 then the
expression (x == 1.5) will return true; because binary form
of 1.5 is 1.1; which is finite and both flaot and double
will have same value.
| Is This Answer Correct ? | 11 Yes | 0 No |
Answer / shibumon alampatta
No output; since (x == 1.1) will return false.
Explanantion:
First of all we shall look into the binary representation of
decimal number 1.1. It is 1.00011001100110011..... reccuring
infinite fractional part. And in the expression (x == 1.1),
x is a float and 1.1 is double constant. So their precisions
are different and float x = 1.1 and the double constant 1.1
will not be equal. So if we make double x = 1.1, instaed of
float it will work. Also if it is float x = 1.5 then the
expression (x == 1.5) will return true; because binary form
of 1.5 is 1.1; which is finite and both flaot and double
will have same value.
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / vignesh1988i
for the first time the loop will be true and it will print as 1.100000 , after reading the next line x will be 1.0, so again when it comes into while loop 1.000000 not equal to 1.100000 so it will come outside the loop
| Is This Answer Correct ? | 4 Yes | 20 No |
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