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how to return 1000 variables from functio9n in c?plz give me
code also
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Answer / vignesh1988i
SEE /... we cant return 1000 variables at a time ... using
call by value...... only call by reference can do it....
tat is. usage of pointers...... since it will change
directly in the address itself.... that's a specality...
#include<stdio.h>
#include<conio.h>
void fun(int *,int *,int *.............1000 int's );
void main()
{
int a1,b1,c1,d1,.............a1000;
fun(&a1,&a2,...... &a1000);
for(int i=0;i<1000;i++)
printf("\n %d",a1);
getch();
}
void fun(int *a1,int *b2,.......... 1000 ptr declarations)
{
*a1=1;
*a2=2
.
.
.
.
.
.
100th varaible =1000;
}
| Is This Answer Correct ? | 9 Yes | 2 No |
Answer / ramachandran
#include<stdio.h>
int fun(int *a)
{
return ++(*a);
}
int main()
{
int a=0,i,d;
for(i=0;i<100;i++)
{
d=fun(&a);
printf("\n%d",d);
}
getch();
}
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / codee
extending the previous answer by passing array instead of
all variables
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / mishra@deepa
the first answer is quite long......
just pass an array(1000 elements) and return that.....
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / y hussain reddy
#include<stdio.h>
void main()
{
int *a;
a=(int*)malloc(200);
void f(int *);
f(a);
for(i=0;i<100;i++)
printf("%d ",a[i]);
}
void f(int *a)
{
int i;
for(i=0;i<100;i++)
a[i]=i;
}
| Is This Answer Correct ? | 0 Yes | 3 No |
Answer / vignesh1988i
you r right sir.... but he has asked 1000 VARIABLES.. so
only i done in this way.....
| Is This Answer Correct ? | 0 Yes | 4 No |
write a program to convert a expression in polish notation(postfix) to inline(normal) something like make 723+* (2+3) x 7 (not sure) just check out its mainly printing expression in postfix form to infix.
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