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difference of two no's with out using - operator
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Answer / arpit
void count()
{
int c=0;
for(i=a;i<=b;i++)
{
c++;
}
return(c);
}
c=b-a :...easy and best .....
| Is This Answer Correct ? | 10 Yes | 5 No |
Answer / gg
Try this....
main()
{
int a,b;
printf("Enter two integers \n");
scanf("%d%d",&a,&b);
printf("The diff is : %d ",a+(~b+1));
}
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / supri
see subtraction itself is the addition of the number with
its 2's complement....
add(int a,int b)
{
if(!a)
return b;
else
return(add((a&b)<<1,a^b));
}
main()
{
int a,b;
scanf("%d%d",&a,&b);
b=add(~b,1);
printf("%d",add(a,b));
return;
}
u can try this...
| Is This Answer Correct ? | 2 Yes | 1 No |
#include<stdio.h>
#include<conio.h>
//To calculate a-b
void main()
{
int a,b,min,max;
printf("Enter the value of a and b \n");
scanf("%d %d",&a,&b);
min = (a<b)?a:b;
max = (a>b)?a:b;
while(min--) max--;
if(a<b)
printf("-%d",max);
else
printf("%d",max);
}
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / sandeep
int count(int a , int b)
{
int c=0;
if(a<b)
for(i=a;i<=b;i++)
{
c++;
}
else
for(i=b;i<=a;i++)
{
c++;
}
return(c); }
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| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / dally
#include<stdio.h>
int main()
{
int a=9,b=4;
if(a>b)
{
while(a--)
b = b--;
}
else
printf("Difference is not possible\n") ;
}
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / vignesh1988i
its simple logic , wat i think is to AND these two inputs.
#include<stdio.h>
#include<conio.h>
void main()
{
int n,m;
scanf("%d %d",&m,&n);
if(m>n)
printf("%d",m&n);
else
printf("%d",n&m);
getch();
}
thank u
| Is This Answer Correct ? | 1 Yes | 10 No |
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