#define f(x) main() { printf("\n%d",f(2+2)); }

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#define f(x)
main()
{
printf("\n%d",f(2+2));
}

Question Posted / raj

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#define f(x) main() { printf("\n%d",f(2+2)); }..

Answer / g.j.hemalatha

f(x) is an identifier.No constants is defined in the macro
definition.So the answer is a garbage value.

Is This Answer Correct ?

2 Yes

0 No

#define f(x) main() { printf("\n%d",f(2+2)); }..

Answer / priyadarshan kasta

it will show a error message as expression syntax error

Is This Answer Correct ?

1 Yes

0 No

#define f(x) main() { printf("\n%d",f(2+2)); }..

Answer / civa

Compiler Error "error: syntax error before ')' token"

Is This Answer Correct ?

1 Yes

1 No

#define f(x) main() { printf("\n%d",f(2+2)); }..

Answer / suman halder

within printf statement,f(2+2) i.e f(4) must return a value so that this value could get printed through %d format specifier..
Now,as f(x) is a macro template and macro expansion code for this template is not specified..so,here the situation is like,we are trying to return an integer value from a function which is having a "void" return type..
so,compiler flashes "Expression syntax error"..as during preprocessing macro template can't be replaced by macro expansion...

Is This Answer Correct ?

0 Yes

0 No

#define f(x) main() { printf("\n%d",f(2+2)); }..

Answer / hema

Is This Answer Correct ?

0 Yes

1 No

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