Given an array of characters which form a sentence of words, give an efficient

Given an array of characters which form a sentence of
words, give an efficient algorithm to reverse the order of
the words (not characters) in it?

Question Posted / san

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Given an array of characters which form a sentence of words, give an efficient algorithm to revers..

Answer / tarak

#include<stdio.h>
int main()
{
char *p="i am working in TechM";
char *s,*temp;
char a[20];
int i=0;
s=p;
while(*p != '\0')
p++;
while(s != p){
while(*(--p)!=' ');
temp=p;
p++;
while(*p != '\0' && *p != ' ')
{
a[i++]=*p;
p++;
}
a[i++]=' ';
p=temp;
p--;
}
while(*s != ' ')
a[i++]=*s++;
a[i] = '\0';
printf("%s \n",a);
}
~

Is This Answer Correct ?

3 Yes

0 No

Given an array of characters which form a sentence of words, give an efficient algorithm to revers..

Answer / anubhav meena

#include <stdafx.h>
#include <string.h>

char* ReverseString(char *a){

int length = strlen(a);
printf("length is:%d\n",length);
int i=0;
int j=length-1;
while(i<j){
*(a+i)=*(a+i)^*(a+j);
*(a+j)=*(a+i)^*(a+j);
*(a+i)=*(a+i)^*(a+j);
i++;
j--;
}

return a;
}

int main()
{
char s[] = "katrina kaif is gorgeous gal!";
char *a=s;
char *b=s;
char *e= a+strlen(a);
printf("String is:%s\n",a);
ReverseString(a);
printf("NewString is:%s\n",a);
int i=0;
while(*(a+i)!='\0'){
while(*(a+i)!=' ' && *(a+i)!='\0') i++;
*(a+i)='\0';
ReverseString(a);

if((a+i)!=e){
*(a+i)=' ';
a = a+i+1;
}
else{
break;
}
i=0;
}
printf("FinalString is:%s\n",b);
getchar();

Is This Answer Correct ?

3 Yes

0 No

Given an array of characters which form a sentence of words, give an efficient algorithm to revers..

Answer / abdur rab

#include <stdio.h>

void reverse_string ( char* cp_string, int start, int end )
{
if ( cp_string && ( start < end ) ) {
*( cp_string + start ) ^= *( cp_string +
end )
^= *( cp_string + start ) ^= *(
cp_string + end );
reverse_string ( cp_string, ++start, --
end );
}
}

int main ( int argc, char* argv [] )
{
char ca_array [12]={"Hello World"};
char* cp_ptr = NULL;
char* cp_ptr_temp = NULL;

printf ( "\n Before Reverse :%s", ca_array );

reverse_string ( ca_array, 0, strlen ( ca_array ) -
1 );

cp_ptr_temp = cp_ptr = ca_array;
while ( NULL != ( cp_ptr_temp = (char*) strchr (
cp_ptr_temp, ' ' ) ) ) {
reverse_string ( cp_ptr, 0, ( cp_ptr_temp -
cp_ptr ) - 1 );
cp_ptr = ++cp_ptr_temp;
}
// change the final word
reverse_string ( cp_ptr, 0,
( ( strlen ( ca_array ) - 1 ) - (
cp_ptr - ca_array ) ) );

printf ( "\n After Reverse by Words :%s",
ca_array );
return ( 0 );
}

Is This Answer Correct ?

1 Yes

0 No

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