What will be result of the following program?
void myalloc(char *x, int n)
{
x= (char *)malloc(n*sizeof(char));
memset(x,\0,n*sizeof(char));
}
main()
{
char *g="String";
myalloc(g,20);
strcpy(g,"Oldstring");
printf("The string is %s",g);
}
a) The string is : String
b) Run time error/Core dump
c) The string is : Oldstring
d) Syntax error during compilation
e) None of these
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Answer / rishabh taneja
correct the line: memset(x,\0,n*sizeof(char)); as
memset(x,'\0',n*sizeof(char));
Result(if the line mentioned is corrected):
The string is: Oldstring
The result is verified by me by actually running it.
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