f(char *p)
{
p=(char *)malloc(sizeof(6));
strcpy(p,"HELLO");
}
main()
{
char *p="BYE";
f(p)
printf("%s",p);
}
what is the output?
Answers were Sorted based on User's Feedback
Answer / deepa
SOORY FOR POSTIN THE WRONG ANSWER THE ANSER WUD BE BYE COZ
THE *P DIES IN THE FUNCTION ITSELF AS WE ARE NOT RETURNING
THE STRING BACK IN THE MAIN PROGRAM
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / vijay
The out put is "BYE".
Because the pointer p dies when function exit with out
return,in main pointer p points to only "BYE",so prinf
prints which p points in main.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / smirnov_amm
It will show "HELL"
the f function reserve only 4 bytes with the sizeof(6). it will return the sizeof (int) =4 bytes.
So you only allocate 4 bytes.
When performing the strcpy, you will corupt memory because you'll copy more than allocate.
Cheers
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / yathish m yadav
the output is "hello".
here we are overwriting pointer *p thrice.
that is in the function we get an piece of memory from
malloc and assigned to p,
in the statement strcpy(p,"hello");
the malloc memory is lost and the compiler creates an char
array and copies the string "hello" and it makes the
character array as constant.
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / deepa
the outpu is hello coz the pointer is pointing to a
location where the string "bye" is written in the next
program yu are using the same pointer to point to some
other string so it gets overwritten
| Is This Answer Correct ? | 2 Yes | 5 No |
Answer / anu
the output wll be hello , since the argument is overwritten
with new memory in the function.
so in main, when it comes to printf, p points to the
allocatd memory, which contains hello
| Is This Answer Correct ? | 0 Yes | 3 No |
The output would be "HELLO"..
though we are not returning the string, we are making
direct changes at the memory location..
so "bye" will be overwritten with "HELLO"
because we are using pointers, the dying pointer scenario
is not applicabe here..
Its a pointer, not a variable..
This function will work similar to -> swapping two numbers
using pointers..
juss check that prog if you fnd somewhere.. :-)
you will get the logic... :-)
Cheers...
--By the way a gud ques.. :-)
| Is This Answer Correct ? | 1 Yes | 4 No |
IS it possible to define a zero sized array in c.if it is possible how can the elements of that array can be accessed.array index starts from zero,if it is possible to define zero sized array how can be its first element can be accesseed.
What is the use of a static variable in c?
What does sizeof return c?
write the program to find multiplication of 2-D matrix??????????
explain what are actual arguments?
What is output redirection?
Explain how do you search data in a data file using random access method?
What is malloc return c?
Explain how are 16- and 32-bit numbers stored?
can we declare a function in side the structure?
Give me the code of in-order recursive and non-recursive.
Write a C program that will accept a hexadecimal number as input and then display a menu that will permit any of the following operations to be carried out: Display the hexadecimal equivalent of the one's complement. (b) Carry out a masking operation and then display the hexadecimal equivalent of the result. (c) Carry out a bit shifting operation and then display the hexadecimal equivalent of the result. (d) Exit. If the masking operation is selected, prompt the user lor the type of operation (bitwise and, bitwise exclusive or, or bitwise or) and then a (hexadecimal) value for the mask. If the bit shifting operation is selected. prompt the user for the type of shift (left or right), and then the number of bits. Test the program with several different (hexadecimal) input values of your own choice.