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main()
{
char *p1="Name";
char *p2;
p2=(char *)malloc(20);
while(*p2++=*p1++);
printf("%s\n",p2);
}
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Answer / subbu[iit kgp]
the given program gives some meaningless output, with some
modification to the given program as
#include<stdio.h>
#include<stdlib.h>
main()
{
char a[]="ramesh";
char *p1="Name";
char *p2=a;
while(*p2++=*p1++);/*copies contents of p1 to
p2*//* here it is not possible to use while(*a++=*p1++)
because a can not change its value*/
*p2='\0';
printf("%s\n",a);
}
The output will be Name
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / vignesh1988i
actually in this problem, the p2 will take characters after '\0' too from p1 upto the size of p2 come to an end.
so it prints
output :
Name #^$&dhd
thank u
| Is This Answer Correct ? | 1 Yes | 1 No |
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