Answer / guest

You will have to declare a temporary variable.

Answer / om prakash mishra

u have to take a temporary variable and pass its adress to
the pointer...like that given below:

// assuming all the conditions are given


int temp=5;
function(&temp);

Answer / jaya prakash

Only Using type modifiers only constant 5 is sent to
function.

[In previous 2 answers address of variable temp (5) is only
send to fn , not a constant 5]

for that fn-call is

function((int*)5);

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