swap 2 variables without using 3 rd variable???
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Answer / rajendra
let
A=10
B=20
after swaping A=20
B=10
ok
A = A + B (A = 20+10 = 30)
B = A - B (B = 20-10 = 10)---->B=10
A = A - B (A = 30-10 = 20)---->A=20
Thats all very simple
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Is This Answer Correct ? | 9 Yes | 3 No |
Answer / guest
Ex:
1.
A=20,B=10
A=A-B=20-10=10
B=A+B=10+10=20
A=B-A=20-10=10
2.
A=6,B=4
A=A-B=6-4=2
B=A+B=2+4=6
A=B-A=6-2=4
The above logic works if A>B. If B>A:
B=6, A=4
B=B-A=6-4=2
A=A+B=4+2=6
B=A-B=6-2=4
Is This Answer Correct ? | 0 Yes | 0 No |
In The Manual Testing process, The team/member is not allowed to do any kind of code/unit or piece of code modifications. etc...,even though the members are aware of bug/ defect exists in the unit/code. Because the question falls under manual testing and even though I know how to do it, it is not out of the box question.
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / gm
Before Swaping
A = 10
B = 20
After Swapping
A = 20
B = 10
Solution:
B = B - A =(20-10) = 10 ---> B = 10
A = A + B =(10+10) = 20 ---> A = 20 (since B = 10 now)
Is This Answer Correct ? | 2 Yes | 3 No |
Answer / naresh
rajendra is correct
but the example he took is wrong...
Is This Answer Correct ? | 0 Yes | 2 No |
Answer / manu
sorry rejendra but i think u r wrong
u hae initially takn a=10 and b=20
ut had taken opposite values moreovr when u have performed
the operation a=a+b
now the value of a has become 30 not the previous 1
i think this will be done with the use of temp variable
Is This Answer Correct ? | 1 Yes | 5 No |
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