Answer / c.p.senthil

#define SETBIT(num,bitpos) (num|(1<<bitpos))
#define CLRBIT(num,bitpos) (num&(~(1<<bitpos)))

int a = 0x03; // a = 00000011b = 0x03(3)
SETBIT(a, 3); // a = 00001011b [3rd bit set] = 0x0b(11)

int b = 0x25; // b = 00100101b = 0x25(37)
CLRBIT(b, 2); // b = 00100001b [2nd bit clear] = 0x21(33)

Answer / sunitha

take i=5;
print its binary value

now for setting a bit
i=i>>5|1;
this will set 5th bit in binary value of 5

now for clearing a bit
i=i>>5 xor 1
this will clear 5th bit in binary value of 5

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