21. #define square(x) x*x main() { int i; i = 64/square(4); printf("%d

21. #define square(x) x*x
main()
{
int i;
i = 64/square(4);
printf("%d",i);
}

Question Posted / sonitaruna3

3 Answers
9606 Views
I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

21. #define square(x) x*x main() { int i; i = 64/square(4); printf("%d",i); }..

Answer / ashok kumar

i=64/4*4;
i=16*4;
i=64

The final result is : 64

Is This Answer Correct ?

18 Yes

2 No

21. #define square(x) x*x main() { int i; i = 64/square(4); printf("%d",i); }..

Answer / rocker1198

Its 64/(4*4)
ans is 4

Is This Answer Correct ?

1 Yes

5 No

21. #define square(x) x*x main() { int i; i = 64/square(4); printf("%d",i); }..

Answer / mathuri

Is This Answer Correct ?

2 Yes

9 No

Post New Answer

More C Interview Questions

What are the different types of endless loops?

0 Answers

#include main() { int i=1,j=2; switch(i) { case 1: printf("GOOD"); break; case j: printf("BAD"); break; } }

6 Answers ME,

What is the use of void pointer and null pointer in c language?

0 Answers

Why main is not a keyword in c?

0 Answers

what is linkage error when it occurs in c program

3 Answers

What is null in c?

0 Answers

output for following code??? main() { int x=2,y,z; x*=3+2; printf("1.%d\n",x); x*=y=z=4; printf("2.%d %d %d\n",x,y,z); x=y==z; printf("3.%d\n",x); x==(y=z); printf("%d",x); }

2 Answers Elysium,

what does " calloc" do?

7 Answers Cadence, Logos,

Can the size of an array be declared at runtime?

0 Answers

main() { static char *s[]={"black","white","yellow","voilet"}; char **ptr[]={s+3,s+2,s+1,s}, ***p; p=ptr; **++p; printf("%s",*--*++p+3); }

1 Answers

difference between the array and linked list general difference related to memory

2 Answers

can u write a program in C, which does not use = (eqaul)or any arithmatic assignment(like -=,+=,*= etc) operator to swap to number?

2 Answers

For more C Interview Questions Click Here