Write a C program to get the desired output.
1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
.
.
.
1 n..............n 1
Note: n is a positive integer entered by the user.
Answers were Sorted based on User's Feedback
Answer / sandip pal
#include<stdio.h>
#include<conio.h>
int ncr(int,int);
int fact(int);
void main()
{
int i,j;
clrscr();
for(i=0;i<=5;i++)
{
printf("\n\n");
for(j=0;j<=5-i;j++)
printf(" ");
for(j=0;j<=i;j++)
printf(" %2d ",ncr(i,j));
}
getch();
}
int ncr(int n,int r)
{
int f;
f=fact(n)/(fact(n-r)*fact(r));
return f;
}
int fact(int n)
{
if(n==0)
return 1;
else
n=n*fact(n-1);
return n;
}
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / ch.mahathi
could anyone please assist me in getting the output in the following way?
For example, if you have entered a pin number like 532211 as the input to the program , then the output should be like this
(5)+(5+3)+(5+3+2)+(5+3+2+1)+(5+3+2+2+1)+(5+3+2+2+1+1)
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / tknowledge05
The above guest is me .. ookk....
by the time i solved and executing i was logged out and when i posted the answer it considered guest.......
Is This Answer Correct ? | 1 Yes | 2 No |
Answer / guest
#include<conio.h>
#include<stdio.h>
void main()
{
int a[10],b[10];
int c=1,n=5;
a[0]=0;a[1]=1;a[2]=0;
b[0]=0;
printf("Enter no. of rows to print ");
scanf("%d",&n);
for(int i=0;i<n;i++)
{
for(int j=n-2;j<0;j++)
printf(" ");
c++;
for(int k=0;k<c;k++)
{
b[k+1]=a[k]+a[k+1];
}
b[c]=0;
for(int k=1;k<=i+1;k++)
{
printf("%d ",a[k]);
}
printf("\n");
for(int k=0;k<i+3;k++)
a[k]=b[k];
}
getch();
}
Is This Answer Correct ? | 4 Yes | 6 No |
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