Answer / vasundhara

int main()
{
int x=1;

if(*(char*)&x)
printf("little endian");
else
printf("big endian");

return 0;
}

Answer / anuraag

Vasudhara's solution is correct!
Still here is an alternative solution to check endianess
without using pointers...

int main()
{
int x=0x58;
char ch;
ch=x;

if(ch=0x58)
printf("Little Endian");
else
printf("Big Endian");
return 0;
}

Answer / udita

little indian

Answer / sudheer

little india

Answer / mohana

The below code snipeet tells whether the system is little
or big endian.

int main()
{
int x=1;

if(x)
printf("big endian");
else
printf("little endian");

return 0;
}

which type of question asked from c / c++ in interview.

2 Answers  

Iam a B.Tech graduate and completed my engineering in 2009, from 2005 to 2009 and after that i had done nothing.Now i want to do job and get into BPO field . Friends give me suggestions as what to say in interview... if they ask me that what would you had done ... these many years without doing job ??????? pls urgent

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Why can arithmetic operations not be performed on void pointers?

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what is the use of operator ^ in C ? and how it works?

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what is a function pointer and how all to declare ,define and implement it ???

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If you know then define #pragma?

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What are file streams?

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How do I declare an array of N pointers to functions returning pointers to functions returning pointers to characters?

2 Answers