what will be the output off the following program?
#include<stdio.h>
int main()
{
int a;
a=015+0*71+5;
printf("%d,a");
return0;
}
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Answer / shiv
015 is octal number its decimal equivalent is = 5 * 8 ^ 0 +
1 * 8 ^ 1 = 5 + 8 = 13
0*71 is 0
then finally , a = 13 + 0 + 5 = 18
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / santhosh
c guys v havi an error on
printf("%d,a");
where the semicolon is ended after "a"...
so
printf("%d",a);
then the ans is 18.
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / dhaval
the main point of answer is that the whole program will run
without a single damn error as it ignores %d (called the
conversion character) and just print "a" as text.
so the answer will be a.
if we write the printf statement as printf ("%d",a); in this
case it shall print the answer as 18. dont know why it
prints 18. am on my way to discover this problem out. i will
post a new answer if at all i shall find an answer to this query
regards,
Dhaval. (L.j college of computer applications.)
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / uma
printf("%d,a"); this gives an error like a value never
used..or if printf statement like printf("%d",a); then it
gives 18 as the answer because 015 is the octal number and
0*71 is 0.
so a=13+5
a=18;
| Is This Answer Correct ? | 0 Yes | 1 No |
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C 
