in step1 of a jcl,disp=(mod,delete,delete) step02 exec pgm=ccc,cond=(0,le) wil

in step1 of a jcl,disp=(mod,delete,delete)
step02 exec pgm=ccc,cond=(0,le)
will step02 be executed?

i)never
ii)always
iii)
iv)...

i dont remember options

Question Posted / sdexcellent@yahoo.co.in

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in step1 of a jcl,disp=(mod,delete,delete) step02 exec pgm=ccc,cond=(0,le) will step02 be executed..

Answer / y@$w@nth

disp=(mod,delete,delete)
will tells that if the file is not previously created create
it if it is already created then use that file.

the two delete statements will tell that delete the file
after norml and abnormal termination.

step02 exec pgm=ccc,cond=(0,le)
Here step02 was coded as condition code which always falls
to true so this step wont execute in any situation......

Is This Answer Correct ?

26 Yes

0 No

in step1 of a jcl,disp=(mod,delete,delete) step02 exec pgm=ccc,cond=(0,le) will step02 be executed..

Answer / k.suamn

it does not exicute

Is This Answer Correct ?

5 Yes

0 No

in step1 of a jcl,disp=(mod,delete,delete) step02 exec pgm=ccc,cond=(0,le) will step02 be executed..

Answer / vinay sonar

Step2 will not execute because always true condition is
coded in step2.
condition code(cc) 0 will be always less than any previous
step cc say 0,4,8,4095 etc. so condition is always true.So
step2 wont execute

Is This Answer Correct ?

3 Yes

0 No

in step1 of a jcl,disp=(mod,delete,delete) step02 exec pgm=ccc,cond=(0,le) will step02 be executed..

Answer / sowmya

step2 will be executed.the steps after the step2 will be by-
passed

Is This Answer Correct ?

1 Yes

9 No

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