Answer / rama krishna sidhartha

The advantage of pointer variables is to reduce the memory
space of another variables.

I don't know how to write the program for counting the
vowels and consonants. If anybody knows please mail to

sidhartha_karyampudi@rediffmail.com

Answer / gaurav kumar

#include <stdio.h>

int vowel;
int consonant;

void check_vowel(char c)
{
if ( c != 'a' && c != 'e' && c != 'i' && c != 'o' && c != 'u' && c != 'A' && c != 'E' && c != 'I' && c != 'O' && c != 'U')
consonant ++;
else
vowel++;
return;
}

int main(void) {
char p[25];
char *ptr=p;

printf("Enter a string:");
scanf(" %[^\n]25s",p);

printf("%s\n",p);
printf("%c\n",*p);

while(*ptr != '\0')
{
if(*ptr != ' ')
check_vowel(*ptr);
ptr++;
}
printf("The number of vowels : %d and consonants : %d in %s \n",vowel,consonant,p);

return 0;
}

Please mail me if any compact solution?

Answer / vadivelt

#include<stdio.h>
#include<conio.h>

CountVowCons(char *ptr, int *count);

int main()
{
char *ptr;
int count[2];
ptr = (char *)malloc(200);
printf("ENTER INPUT STRING\n");
ptr = gets(ptr);
CountVowCons(ptr, count);
printf("\nNO OF VOWELS:%d \nNO OF CONS: %d",count[0], count
[1]);
getch();
}

CountVowCons(char *ptr, int *count)
{
int Vowcount = 0, Conscount = 0;
while(*ptr != '\0')
{
if((*ptr == 'a') || (*ptr == 'A') || (*ptr == 'e') ||
(*ptr == 'E') || (*ptr == 'i') ||
(*ptr == 'I') || (*ptr == 'o') || (*ptr == 'O') ||
(*ptr == 'u') || (*ptr == 'U'))
{
Vowcount++;
}

else if((*ptr >= 65 && *ptr <= 90) ||
(*ptr >= 97 && *ptr <= 122))
{
Conscount++;
}

ptr++;
}

*count++ = Vowcount;
*count = Conscount;
count--;
}

main() { int i = -3,j=2,k=0,m; m= ++i || ++j && ++k; printf("%d%d%d",i,j,k,m); }

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