write a program to swap two numbers without using temporary
variable?
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Answer / it diploma student
let a and b be the variables
a=a+b
b=a-b
a=a-b
if we take a=5 and b = 7 then
a = 5+7 = 12
b = 12-7 = 5
a = 12-5 = 7
hence swaped...
| Is This Answer Correct ? | 26 Yes | 3 No |
Answer / guest
[code]
main()
{
int a=10;
int b=20;
printf("a = %d\nb = %d\n",a,b);
a =a+b; b=a-b; a=a-b; // This is first way.
a =a*b; b=a/b; a=a/b;
printf("a = %d\nb = %d\n",a,b);
}
[/code]
[code]
main()
{
int a=10;
int b=20;
printf("a = %d\nb = %d\n",a,b);
a =a*b; b=a/b; a=a/b; //This is second way
printf("a = %d\nb = %d\n",a,b);
}
[/code]
| Is This Answer Correct ? | 19 Yes | 2 No |
Answer / sam
let a and b be variables
a^=b^=a^=b;
by performing this logic from right hand side we can swap
two variables
| Is This Answer Correct ? | 6 Yes | 5 No |
#include<stdio.h> #include<conio.h> void main() { clrscr(); int a=0,b=0,c=0; printf("enter value of a,b"); scanf(" %d %d",a,b); c=a+b; printf("sum is %d",c); getch(); }
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