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A man while going dowm in a escalator(which is miving down)
takes 50 steps to reach down and while going up takes 125
steps. If he goes 5 times faster upwards than downwards.
What will be the total no of steps if the escalator werent
moving.
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Answer Posted / sabarish
169 approx.
let d be the steps in the esculator.
distance covered by man upwards = d+50
and downwards = d - 125
let s1 and s2 be the speed for upwards and downwards.
s1=s2 x 5
(d+50) / t = s1 ..........1
( d-125 ) / t = s2..........2
d= s1 x t - 50 d = s2 x t + 125
(s1 x t) - 50 = (s1 x t)/5 +125 solving (s1 x t) = 219.
sub in 1 we get d = 169.
| Is This Answer Correct ? | 0 Yes | 11 No |
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