Answer / haribabu

Once you have assigned a value to a "String Object" (i am
saying an "object" not the "object reference")that value
can never change. This is immutability.

by defining "s = s+Technologies" we are pointing the
REFERENCE to newly created "string object" with the
modified string. So the previous string object is
considered to be lost.

This concept has explained very well in String, I/Os
chapter of Kethy Siera, SCJP 5.

All the best

Answer / harmetkrishanan

every time a new String object gets created in this case.

Answer / bln

Every time a new String objects gets created in this case,
but if assigned value is not same. If assigned, value is
same, then it points to same memory location, even if it is
another variable. For ex;
String s="Test";
String s2="Test";

Now s, s2 points to the same memory location.

Answer / r.jainrocks@gmail.com

When concatenation operator "+"
used with string

it always creates a new String object,
in String pool area.

Answer / anjani kumar jha

Now u add s= s+"Technologies";
so it will NessTechnologies because you append. and assign
new varible,means that new addition is assigned to s

take one example for more clarity

String x = "Java";
x.concat(" Rules!");
System.out.println(x);

output is x=java
because string is immutable.............think hard on it


Consider the following another example---------and think
about that

public class NewClass {

public static void main(String as[])
{
String s="abc";
String s1=s+"cde";
System.out.println(s);
System.out.println(s1);


String x = "Java";
x.concat(" Rules!");
System.out.println(x);
}

}
output is
s=abc;
s1=abcde
x=java

since u have added cde in s but still from the output it is
abc...............means string is immutable,

For more contact me
Anjani Kumar jha
09623154095
CDAC,PUNE

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