a watch which looses uniformly was observed to be 12 min
fat at 4am.on 6th of a month.it showed 20 min less than
thae correct time at 6pm on the 10th of the same month.when
did the watch show correct time

Answers were Sorted based on User's Feedback



a watch which looses uniformly was observed to be 12 min fat at 4am.on 6th of a month.it showed 2..

Answer / karthik

its 9:15 pm on 7th of the month

Please don't mess peoples lives.
Use Ur common sense to answer the questions.

Is This Answer Correct ?    19 Yes 5 No

a watch which looses uniformly was observed to be 12 min fat at 4am.on 6th of a month.it showed 2..

Answer / swap

9:15pm of 7th

Is This Answer Correct ?    10 Yes 2 No

a watch which looses uniformly was observed to be 12 min fat at 4am.on 6th of a month.it showed 2..

Answer / rejish r

Correct time at 7:44 AM on the 6th of the month

Explanation:

Day 6
4:00 AM - 12 min slow

Day 10

6:00 PM - 20 mins fast

change in time = 12+20 = 32 min

4:00 AM, day 6 to 4:00AM, day 10 = 24*4=96hrs
day 10 : 4AM to 6PM = 14 hrs

Total hrs from day 6 to 10 = 96+14=110hrs
Now, we see a change of 32 mins in 110 hrs
rate of change: 110/32= 3 hr 44 mins

therefore:

4:00 AM + 3 hr 44 min = 7:44 AM
:)

Is This Answer Correct ?    6 Yes 8 No

a watch which looses uniformly was observed to be 12 min fat at 4am.on 6th of a month.it showed 2..

Answer / anu

9.30 pm at 2nd of the month

Is This Answer Correct ?    2 Yes 5 No

a watch which looses uniformly was observed to be 12 min fat at 4am.on 6th of a month.it showed 2..

Answer / ramesh ps

1. Watch was observed +12 minutes at 4 am on 6th of the
month
2. Watch was observed -20 minutes at 6 pm on 10th of the
month

The watch ad lost 32 minutes in n number of hours
Number of hours between these intervals = 20+24+24+24+18=110
Since watch is slowed down by 32 minutes (from +12 to -20)
in 110 hours
Number of hours took to slowed down one minute = 110/32
Number of hours took to slowdown 12 minutes at which the
watch was showing correct time is = (110/32)*12 = 41.25

If I add 41.25 to 4 Am of 6th Of the month then it will
become 11:25 PM on 7th of the month.

Is This Answer Correct ?    3 Yes 6 No

a watch which looses uniformly was observed to be 12 min fat at 4am.on 6th of a month.it showed 2..

Answer / alphy

ans: 8:10 pm on 7th of the month

12min fast at 4 am on 6th
20min slow (less)at 6pm on 10th

i.e-> 32 mins changed in 110 hrs ( from 6th to 10th )

we have to find d time passed where change is 12 min .. dat
nullifies the 12 min fast effect ...

32 -> 110 hrs
12 -> 40hrs and 10 mins

4:00 am + 40 hrs + 10 mins -> 8:10 pm on 7th of the month

Is This Answer Correct ?    0 Yes 5 No

a watch which looses uniformly was observed to be 12 min fat at 4am.on 6th of a month.it showed 2..

Answer / shiva

ANSwer is 9 AM 15 Mins

at 4 am it is 12 min fast.

at 6pm it is 20 min slow.

it means 12+20 min reduced in 6pm-4am hrs i.e 14 hrs

finally in 14 hrs it is decreased 32 mins.

14 hrs-- 32 hr
??? hrs- 12 hr it gives 14*12/32

it means
5.25 hrs+ 4am it is giving the right answer 9 am 15 mins

Is This Answer Correct ?    5 Yes 11 No

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