Answer / pankaj kumar sharma

Function overloading takes place when a function is
overloaded with two or more tasks ie. same function is
having different behaviour.
It takes place when two functions have same name but
differs in argument list ie. may be the no of arg in both
fun are different or type of the arguments in argument list
are diff.

As return type of a func. does not take part in name
mangling so return type for overloaded functions may differ
or not.

eg: int fun(int arg1, int arg2)
char* fun(char* ptr1)

Answer / rabih

two functions with same but different signature

example let take function name test return int and take a
parameter of type int (int test(int x))

let take same function of name test with different
signature void test(int x) or int test(bool n) or
int test(int x,string y)

all these functions can written in same class without any
error this means same function name(test)
different signature is deffernet return type or different
paraemeter type

Answer / achal ubbott

Here i tell how function overloading works. The point is
name mangling. Each c++ compiler follows an algorithm
called Name Mangling algorithm. Its job is to create
different symbols for functions. The mangled name of the
function would depend upon number,type and order of
function arguments. You can see these mangled names in the
assembly code. But C does not mangle function Names.
Unfortunately there is no ISO standard for name mangling.
So most c++ compilers do that in a different way

Answer / anjana

FUNCTION OVER LOADING:
TWO OR MORE FUNCTIONS HAVING THE SAME NAME IS CALLED THEY ARE SAID TO BE FUNCTION OVER LOADING.

#include <iostream> using namespace std; struct wow { int x; }; int main() { wow a; wow *b; a.x = 22; b = &a; a.x = 23; cout << b->x; return 0; }

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