A man is stranded on a desert island. All he has to drink is
a 20oz bottle of sprite.
To conserve his drink he decides that on the first day he
will drink one oz and the refill the bottle back up with
water. On the 2nd day he will drink 2oz and refill the
bottle. On the 3rd day he will drink 3oz and so on...
By the time all the sprite is gone, how much water has he drunk?
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Answer / guest
The man drunk 190oz of water.
It is given that the man has 20oz bottle of sprite. Also, he
will drink 1oz on the first day and refill the bottle with
water, will drink 2oz on the second day and refill the
bottle, will drink 3oz on the third day and refill the
bottle, and so on till 20th day. Thus at the end of 20 days,
he must have drunk (1 + 2 + 3 + 4 + ..... +18 + 19 + 20) =
210oz of liquid.
Out of that 210oz, 20oz is the sprite which he had
initially. Hence, he must have drunk 190oz of water.
| Is This Answer Correct ? | 9 Yes | 8 No |
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