Answer / antony

#include<stdio.h>
#include<conio.h>
void main()
{
int a[10],i;
for(i=1;i<=10;i++)//getting data from user
{
scanf("%d",&a[i]);
}
for(i=1;i<=10;i++)//print the data
{
printf("%d",a[i])
}
getch();
}

Answer / rina

#include<stdio.h>
#include<conio.h>
void main()
{
int i,a[5],n;
clrscr();
printf("\nenter the no.");
scanf("%d",&n);
for(i=1;i<=5;i++)
{
scanf("%d",&a[i]);
}
for(i=1;i<=5;i++)
{
printf("%d",a[i]);
}
getch();
}

Answer / shrish cahndra tripathi

#include<sotdio.h>
#include<conio.h>
void main()
{
int a[5];
int b=1;
while b<5;
printf("/n enter value of a1");
scanf("%d",a0);
printf("/n enter value of a1");
scanf("%d",a1);
printf("/n enter value of a1");
scanf("%d",a2);
printf("/n enter value of a1");
scanf("%d",a3);
printf("/n enter value of a1");
scanf("%d",a4);
printf("/n values are :- %d, %d, %d, %d, %d"a[i]);
getch();
clrscr();
}

find the output of the following program main() { int x=5, *p; p=&x; printf("%d",++*p); }

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