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main()
{
int arr[5]={23,67};
printf("%d%d%d",arr[2],arr[3],arr[4]);
}
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Answer / vikas upendra
The rest will be initialized to zero ....so it'll be 000 ..
| Is This Answer Correct ? | 25 Yes | 4 No |
Answer / jaga
in linux it will give garbage values...
in unix it will give 000(automatically initialized to 0)
| Is This Answer Correct ? | 11 Yes | 2 No |
Answer / vignesh1988i
all wil print the garbage values in the respected
memories... since we only initilized for two locations in
th array.... so other locations in the array wil have
garbage values
| Is This Answer Correct ? | 13 Yes | 9 No |
Answer / bsn.teja
till array elements are not given any specific values,they
are supposed to contain garbage values.
here we initialised only 1st two elements of the array.
so output will be garbage values.
| Is This Answer Correct ? | 2 Yes | 0 No |
first a[0]=23;
a[1]=67;
rest index are assigned 0 0 0.
| Is This Answer Correct ? | 1 Yes | 0 No |
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C 
