Answer / vignesh1988i

SEE /... we cant return 1000 variables at a time ... using
call by value...... only call by reference can do it....
tat is. usage of pointers...... since it will change
directly in the address itself.... that's a specality...


#include<stdio.h>
#include<conio.h>
void fun(int *,int *,int *.............1000 int's );
void main()
{
int a1,b1,c1,d1,.............a1000;
fun(&a1,&a2,...... &a1000);
for(int i=0;i<1000;i++)
printf("\n %d",a1);
getch();
}
void fun(int *a1,int *b2,.......... 1000 ptr declarations)
{
*a1=1;
*a2=2
.
.
.
.
.
.
100th varaible =1000;
}

Answer / ramachandran

#include<stdio.h>
int fun(int *a)
{
return ++(*a);
}

int main()
{
int a=0,i,d;
for(i=0;i<100;i++)
{
d=fun(&a);
printf("\n%d",d);
}
getch();
}

Answer / codee

extending the previous answer by passing array instead of
all variables

Answer / mishra@deepa

the first answer is quite long......

just pass an array(1000 elements) and return that.....

Answer / y hussain reddy

#include<stdio.h>
void main()
{
int *a;
a=(int*)malloc(200);
void f(int *);
f(a);

for(i=0;i<100;i++)
printf("%d ",a[i]);
}
void f(int *a)
{

int i;
for(i=0;i<100;i++)
a[i]=i;
}

Answer / vignesh1988i

you r right sir.... but he has asked 1000 VARIABLES.. so
only i done in this way.....

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