Answer / vignesh1988i

#include<stdio.h>
#include<conio.h>
void main()
{
int m;
printf("enter the limit value :");
scanf("%d",&m);
for(int i=0;i<(2*n+1);i++)
{
printf("\n");
if(i<n)
{
for(int j=0;j<=i;j++)
printf("%d",j);
}
else
{
for(int k=0;k<=j;k++)
printf("%d",k);
j--
}
}
getch();
}

Answer / vignesh1988i

A SMALL chnge in the above program... in first for loop 'n'
must be changed as 'm'

Answer / manoj

#include <stdio.h>
int main ()
{
/*declaration*/
int n = 5 ;
int i, j;

/*clean screen*/
clrscr();

/*actual functionality*/
for( i =0; i<=n; i++)
{
printf("\n");
for(j=0; j<=i; j++)
printf("%d",j);
}

for( i =4; i<n&&i>=0; i--)
{
printf("\n");
for(j=0; j<=i; j++)
printf("%d",j);

}

/*return to TC*/
getch();

return 0;
}

Answer / salvin

A much more simpler implementation....


public class Test
{
public static void main(String[] args)
{
int no=5;
for(int n=0;n<=no;n++){
for(int m=0;m<=n;m++){
System.out.print(m);
}
System.out.println();
}
for(int n=no;n>=0;n--){
for(int m=0;m<n;m++){
System.out.print(m);
}
System.out.println();
}
}
}

we compile c program in 32 processor and 64 bit processor .exe file is created in both the processors. if we want to run .exe file in 64 bit processor which is created in 32 bit processor. is that .exe file is run or not if it is not run why?

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