Answer / vignesh1988i

#include<stdio.h>
#include<conio.h>
void main()
{
int m;
printf("enter the limit value :");
scanf("%d",&m);
for(int i=0;i<(2*n+1);i++)
{
printf("\n");
if(i<n)
{
for(int j=0;j<=i;j++)
printf("%d",j);
}
else
{
for(int k=0;k<=j;k++)
printf("%d",k);
j--
}
}
getch();
}

Answer / vignesh1988i

A SMALL chnge in the above program... in first for loop 'n'
must be changed as 'm'

Answer / manoj

#include <stdio.h>
int main ()
{
/*declaration*/
int n = 5 ;
int i, j;

/*clean screen*/
clrscr();

/*actual functionality*/
for( i =0; i<=n; i++)
{
printf("\n");
for(j=0; j<=i; j++)
printf("%d",j);
}

for( i =4; i<n&&i>=0; i--)
{
printf("\n");
for(j=0; j<=i; j++)
printf("%d",j);

}

/*return to TC*/
getch();

return 0;
}

Answer / salvin

A much more simpler implementation....


public class Test
{
public static void main(String[] args)
{
int no=5;
for(int n=0;n<=no;n++){
for(int m=0;m<=n;m++){
System.out.print(m);
}
System.out.println();
}
for(int n=no;n>=0;n--){
for(int m=0;m<n;m++){
System.out.print(m);
}
System.out.println();
}
}
}

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