write a own function to compare two strings with out using
stringcomparition function?
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Answer / ravikiran p sattigeri
/* str_cmp : Comapares the character strings s1 and s2, and
returns negative, zero or positive if s1 is
lexicographically less than, equal to, or greater than s2.
The value is obtained by subtracting the characters at the
first position where s1 and s2 disagree */
/* return < 0 if s1<s2, 0 if s1==s2, >0 if s1>s2 */
int str_cmp (char *s1, char *s2)
{
while(*s1++ == *s2++) {
if (*s1 == '\0')
return 0;
}
return *S1 - *s2;
}
| Is This Answer Correct ? | 13 Yes | 3 No |
Answer / geetha
main()
{
char a[10],b[10];
int i,l2,l1;
printf("Enter two strings");
scanf("%s\n",a);
scanf("%s",b);
l1=strlen(a);
l2=strlen(b);
if(l1==l2)
{
for(i=0;i<l1;i++)
{
if(a[i]==b[i])
continue;
else
printf("no match");
break;
}
}
else
printf("no match");
if(i==11)
printf("both strings are same");
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vignesh1988i
sorry ... i made a small logical problem in a above posted
answer ... so this program will work out correctly.....
#include<stdio.h>
#include<conio.h>
int xstrcmp(char*,char*);
void main()
{
int c;
char a1[20],a2[20];
printf("enter the two strings :");
gets(a1);
gets(a2);
c=xstrcmp(&a1[0],&a2[0]);
printf("%d",c);
getch();
}
int xstrcmp(char *a,char *a1)
{
if((*a)!=(*a1))
return((*a)-(*a1));
else if((*a)!='\0' || (*a1)!='\0')
{
(a)++;
(a1)++;
xstrcmp(a,a1);
}
else
return 0;
}
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / vignesh1988i
#include<stdio.h>
#include<conio.h>
int xstrcmp(char*,char*);
void main()
{
int c;
char a1[20],a2[20];
printf("enter the two strings :");
gets(a1);
gets(a2);
c=xstrcmp(&a1[0],&a2[0]);
printf("%d",c);
getch();
}
int xstrcmp(char *a,char *a1)
{
if((*a)!=(*a1))
return((*a)-(*a1));
else if((*a)!='\0' && (*a1)!='\0')
{
(*a)++;
(*a1)++;
xstrcmp(a,a1);
}
else
return 0;
}
| Is This Answer Correct ? | 5 Yes | 6 No |
Answer / sasikumar
main()
{
char s1[10],s2[10];
printf("enter two strings:");
scanf("%s%s",&s1[10],&s2[10]);
compare(s1[10],s2[10]);
getch();
}
compare(char st1[10],char st2[10])
{
int l1,l2,i;
l1=strlen(st1[10]);
l2=strlen(str2[10]);
if(l1==l2)
{
for(i=0;i<l1;i++)
{
if(st1[i]==st2[i])
{
if(i==l1)
{
printf("two strings are equal");
}
}
else
goto label:
}
}
else
goto label:
label:printf("not equal");
}
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / mallesh
#include<stdio.h>
#include<conio.h>
int xstrcmp(char*,char*);
void main()
{
int c;
char a1[20],a2[20];
printf("Enter the two string's :\n");
gets(a1);
gets(a2);
c=xstrcmp(&a1[0],&a2[0]);
printf("%d",c);
getch();
}
int xstrcmp(char *a,char *a1)
{
while((*a)==(*a1))
{
if((*a=='\0')||(*a1=='\0'))
break;
++(a);
++(a1);
}
return((*a)-(*a1));
}
| Is This Answer Correct ? | 0 Yes | 1 No |
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