Answer / vaibhav

#include<stdio.h>
#include<conio.h>
void main()
{
int no,t,cnt=0;
clrscr();
printf("\n enter the no.");
scanf("%d",&no);
while(no!=0)
{
t=no%10;
no=no/10;
cnt++;
}
printf("\nTotal count of digit is%d",cnt);
getch();
}

Answer / santhi perumal

#include<stdio.h>
#include<conio.h>

int main()
{
int number,m,sum =0,count =0;

printf("Enter the number \n");
scanf("%d",&number);

while(number != 0)
{
m = number % 10;
sum = sum + m;
count++;
number = number / 10;
}

printf("\nThe number of Digits in the Given Number is
%d\n",count);
printf("The Sum of Digits in the Given Number is %d\n",sum);



}

Answer / govind279

#include<stdio.h>
int main()
{
int n,m,sum=0;
scanf("%d",&n);
for(m=0;((m=n%10)!=0);n=(n/10))
sum+=m;
printf("count is %d\n",sum);
}

Answer / sashidharan

main()
{
int n,count=0;
scanf("%d",&n);
for(i=0;i<=n;i++)
{
count=count+1;
}
printf("total count of digit",count);
}

What is output of the following program ? main() { i = 1; printf("%d %d %d\n",i,i++,i++); }

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