.find the output of the following program?
char*myfunc(char*ptr)
{
ptr +=3;
return (ptr);
}
int main()
{
char*x,*y;
x="HELLO";
y=myfunc(x);
printf("y = %s
",y);
return 0;
}
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Answer / Vikas Singh
The given C program creates a function named myfunc that takes a character pointer as an argument and increases its value by 3. When this function is called with the string "HELLO", it returns a new pointer pointing to the modified string "HELLO+3". In the main function, the returned pointer is stored in the y variable, and then printed out. The output of the program would be: y = LOOO.
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