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write a program for size of a data type without using
sizeof() operator?
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Answer / mazhar shaikh
datatype a,*p,*q;
p=&a;
q=p+1;
cout<<abs(int(p)-int(q))<<endl;
| Is This Answer Correct ? | 5 Yes | 7 No |
Answer / vignesh1988i
#include<stdio.h>
#include<conio.h>
void main()
{
int integer[2],p;
float floating[2],q;
char character[2],r;
double doubling[2],s;
clrscr();
p=(integer+1)-integer;
q=(floating+1)-floating;
r=(character+1)-character;
s=(doubling+1)-doubling;
printf("the sizeof int is :%d",p);
printf("\nthe size of float is :%d",q);
printf("\nthe size of character is :%d",r);
printf("\nthe size of double is :%d",s);
getch();
}
thank u
| Is This Answer Correct ? | 5 Yes | 11 No |
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