Answer / abhishek pathak mnnit

#include <stdio.h>
#define sizeof(x) ((void *)(&x + 1) - (void *)(&x))
void main()
{
int a;
printf("int size=%d",sizeof(a));
}

Answer / vignesh1988i

#include<stdio.h>
#include<conio.h>
void main()
{
int ptr,a[2];
char ptr1,b[2];
float ptr2,c[2];
ptr=(a+1)-a;
ptr1=(b+1)-b;
ptr2=(c+1)-c;
printf("int : %d\n",ptr);
printf("char : %d\n",ptr1);
printf('float : %d\n",ptr2);
getch();
}


than ku

Answer / ravi.jnv

Its possible by pointers.
-----------------
int one,two;
int *ptrOfOne,*ptrOfTwo;
int size;
ptrOfOne = &one;
ptrOfTwo = &two;
size = ptrOfOne - ptrOfTwo ; /* u can get minus value also
depending upon stack how it pushes variables */

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