In the following declaration of main, "int main(int argc,
char *argv[])", to what does argv[0] usually correspond?
1) The first argument passed into the program
2) The program name
3) You can't define main like that
Answers were Sorted based on User's Feedback
Answer / sanish joseph
No guys the ans s 2
it prints d program name:
arguments counts only from 1 nd nt 4m 0
| Is This Answer Correct ? | 15 Yes | 0 No |
Answer / vadivel
If the value of argc is greater than 0, the array members
argv[0] through argv[argc-1] inclusive shall contain
pointers to strings, which will be the command line
arguments. argv[0] will contain the program name, argv[1]
the first command line arg, argv[1] the second and so on.
Finally, argv[argc] is guaranteed to the a NULL pointer,
which can be useful when looping through the array.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / sumeet sharma
argv[o] the array of strings will point to the name of the
program.
argv[1] will point to the first argument and so on.
| Is This Answer Correct ? | 1 Yes | 0 No |
write a code for this:trailer recordId contains a value other than 99, then the file must error with the reason ‘Invalid RECORD_ID’(User Defined Exception).
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#include <string.h> #include <stdio.h> #include <stdlib.h> #include <conio.h> void select(char *items, int count); int main(void) { char s[255]; printf("Enter a string:"); gets(s); select(s, strlen(s)); printf("The sorted string is: %s.\n", s); getch(); return 0; } void select(char *items, int count) { register int a, b, c; int exchange; char t; for(a = 0; a < count-1; ++a) { exchange = 0; c = a; t = items[ a ]; for(b = a + 1; b < count; ++b) { if(items[ b ] < t) { c = b; t = items[ b ]; exchange = 1; } } if(exchange) { items[ c ] = items[ a ]; items[ a ] = t; } } } design an algorithm for Selection Sort
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