Why non nested classes in java are not having marked as
protected access specifier
Answers were Sorted based on User's Feedback
Answer / udita bose
Sorry, but previous answer by Yayati Pavan does not answer the question. If that answer is true then there should not be a problem with a "protected" class, as "protected" keyword is wider than default one.
There are no protected class because it is unnecessary to have them. Access modifiers for classes determine 2 things
i) If a class can create instance of other class ?
ii)If a class can extend other class ?
Now, any class within the same package will be able to create an instance of "protected" class - this is true for default-accessor and public classes. No class outside the package will be able to create an instance of "protected" class - this holds good for default-accessor classes.
Again, for a "protected" class by its definition will be extendible by any class within its package - so is default-accessor class, and extendible for any class outside its package - so are all public classes.
Both of this reason nullifies the reason for a protected class.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / yayati pavan
When the non nested class declared as public or
default(public) the jvm can access the class and execute.
So non nested class must always public. other wise jvm can't
access the class.
| Is This Answer Correct ? | 7 Yes | 9 No |
Explain about GridBag Layout?
What is the use of default method in interface in java?
What is the numeric promotion?
What is a lightweight component?
Can you call a method on a null object?
Difference between static synchronization vs. Instance synchronization?
What is the purpose of assert keyword used in jdk1.4.x?
Give example to differentiate between call by value and call by reference.
How do you ensure that n threads can access n resources without deadlock?
Is void a data type?
What are order of precedence and associativity, and how are they used?
What is unicode used for?