if length of a rectangle is incr by 20% and width is decr by
20% then area

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if length of a rectangle is incr by 20% and width is decr by 20% then area ..

we know,
area=b*h
b gets increased by 20% i.e (b+0.20b)
h gets decreased by 20% i.e (h-0.20h)

rewriting the equation(area=b*h),

area=(b+0.20b)*(h-0.20h)
area=b(1+0.20)*h(1-0.20)
area=b(1.20)*h(0.80)
area=b*h*(1.20)*(0.80)
area=b*h*(0.96)

i.e new area=0.96 times the original area
if 100% was the original area,it has decreased to 96%
so,100%-96%= 4%

 Is This Answer Correct ? 38 Yes 2 No

if length of a rectangle is incr by 20% and width is decr by 20% then area ..

Decreased by 4%
Refer GMAT'96 edition ..i think page 44

 Is This Answer Correct ? 36 Yes 3 No

if length of a rectangle is incr by 20% and width is decr by 20% then area ..

it is dec by 4%

120% * 80% = 96%

ie dec by 4... sure now??

 Is This Answer Correct ? 17 Yes 2 No

if length of a rectangle is incr by 20% and width is decr by 20% then area ..

i think d area will be 24/25.
since l=120/100=>6/5
and b= 80/100=>4/5

 Is This Answer Correct ? 6 Yes 7 No

if length of a rectangle is incr by 20% and width is decr by 20% then area ..

Increase by 1%

(Pls inform me if someone else with a different ans is v
sure)

 Is This Answer Correct ? 4 Yes 13 No

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