if length of a rectangle is incr by 20% and width is decr by
20% then area
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Answer / zammil
we know,
area=b*h
b gets increased by 20% i.e (b+0.20b)
h gets decreased by 20% i.e (h-0.20h)
rewriting the equation(area=b*h),
area=(b+0.20b)*(h-0.20h)
area=b(1+0.20)*h(1-0.20)
area=b(1.20)*h(0.80)
area=b*h*(1.20)*(0.80)
area=b*h*(0.96)
i.e new area=0.96 times the original area
if 100% was the original area,it has decreased to 96%
so,100%-96%= 4%
Is This Answer Correct ? | 38 Yes | 2 No |
Answer / guest
Decreased by 4%
Refer GMAT'96 edition ..i think page 44
Is This Answer Correct ? | 36 Yes | 3 No |
Answer / asdf
it is dec by 4%
120% * 80% = 96%
ie dec by 4... sure now??
Is This Answer Correct ? | 17 Yes | 2 No |
Answer / meenakshy
i think d area will be 24/25.
since l=120/100=>6/5
and b= 80/100=>4/5
Is This Answer Correct ? | 6 Yes | 7 No |
Answer / amit kumar das
Increase by 1%
(Pls inform me if someone else with a different ans is v
sure)
Is This Answer Correct ? | 4 Yes | 13 No |
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