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A room is 30 X 12 X 12. a spider is ont the middle of the
samller wall, 1 feet from the top, and a fly is ont he
middle of the opposite wall 1 feet from the bottom. what is
the min distance reqd for the spider to crawl to the fly.
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Answer / imran
length is 30 breadth is 12 and height is 12
------------------------------
1
.------------------------------
1 .
1 .
1 10 .
1
1 .
1
1
1 30 .
-------------------------------.
1
consider right angled triangle
so the distance= square root of (30*30+10*10)
| Is This Answer Correct ? | 11 Yes | 4 No |
Answer / sarathchand
h=30; b=12; h=12;
..............
| " |
| |
| | 12
| |
| " |
|..............|
30
Apply Geometry to get the minimum distance.
Mid-point [A] of side wall is at 6.
Spider [B] is at 5 from Mid-point of side wall (or) 11 from bottom (or) 1 form top.
Center point [C] of box is 15 away form the mid-point of side wall.
Then ABC is a right angled triangle.
Sides AB=5; AC=15;
Angle at A=90 degrees
BC=((AB^2)+(AC^2))^1/2
BC=15.811
Similarly,
Mid-point[D] of ooposite sidewall is at 6.
Fly [E] is at 5 from Mid-point of opposite side wall (or) 11 from top (or) 1 form bottom.
Center point [C] of box is 15 away form the mid-point of opposite side wall.
Then DEC is a right angled triangle.
Sides DE=5; DC=15;
Angle at D=90 degrees
CE=((DE^2)+(DC^2))^1/2
CE=15.811
Shortest distance from B(Spider) to E(Fly)
BE = BC + CE
BE = 31.622
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / hitesh
Answer is 40.
1. We need to "flatten" the cuboid room(or open it up as a plane sheet i.e. how all 6 faces of cuboid can be opened up).
2. The question is asked about the shortest distance spider
can take to reach Fly by "CRAWLING".
As Sarathchand answered the shortest distance as 31.622, that means the spider must have the ability to "fly" to reach that Fly which unfortunately not mentioned in the porblem.
3. So, if we flatten the cuboid and join those 2 points(say A (spider and B Fly), you can get the distance as 40 by using right angle triangle property(for triangle ABC for 'flattened' or(Opened Up) cuboid.
Sqrt(32*32+24*24)=40.
In which base AC will be = 32 i.e.(1+30+1) where 1 is dist. from top to spider, 30 is length and 1 is dist. from bottom to Fly.
And height BC will be = 24 i.e. (6+12+6) where 6 is centre distance(Mid point) and 12 is one side.
When we flatten the cuboid it'll look like this(can't post the picture, no option available. I tried my best, I hope u can understand.)
____________
|____________|__ 12
|____________|B_| 12 (mid point 6) 6+
__|____________|1 12 12+
|_A|____________|C 12 (mid point 6) 6= 24 (=BC)
1 30
1+ 30+ 1= 32 (=AC)
| Is This Answer Correct ? | 1 Yes | 0 No |
In A,B,C are having some marbles with each of them. A has giben B and C the same number of marbles they already have to each of them. then, B gave C and A the same no. of marbles they have, then C gave A and B the same no. of marbles they have. At the end A,B,and C have equal no. of marbles. (i) If x,y,z are the marbles initially with A,B,C respectively. then the no of marbles B have at the end (a) 2(x-y-z) (b) 4(x-y-z) etc. (ii)If the total no. of marbles are 72, then the no. of marbles with A at the starting a. 20 b. 30 c. 32
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