RAM chips arranged in 4X6 array and of 8kX4bit capacity
each. How many address lines reqd. to access each byte
a. 12 b. 16 c.15 d. 17
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Answer / subhash
d. 17
8k*4 8k*4 8k*4 8k*4 8k*4 8k*4 - 24KB
8k*4 8k*4 8k*4 8k*4 8k*4 8k*4 - 24KB
8k*4 8k*4 8k*4 8k*4 8k*4 8k*4 - 24KB
8k*4 8k*4 8k*4 8k*4 8k*4 8k*4 - 24KB
------
96kB
To address it byte by byte you need 17 address lines
16 lines - 2^16 = 64kB
17 lines - 2^17 = 128kB
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Answer / ganesh
Generally number of address lines = Number of available words.
If word length is 8 bit -
8192*12 (2 chips to enable word length as 8 bit)
~ 17 bits (16.58)
| Is This Answer Correct ? | 1 Yes | 0 No |
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