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Difference in the use of print, println, and printf.
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Answer / nashiinformaticssolutions
The items can be printed using print, println, or printf, but print prints every element while keeping the cursor in the same line. The cursor is moved to the next line via println. Additionally, we can use format identifiers with printf.
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Answer / glibwaresoftsolutions
The items can be printed using print, println, or printf, but print prints every element while keeping the cursor in the same line. The cursor is moved to the next line via println. Additionally, we can use format identifiers with printf.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / glibwaresoftsolutions
The items can be printed using print, println, or printf, but print prints every element while keeping the cursor in the same line. The cursor is moved to the next line via println. Additionally, we can use format identifiers with printf.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / glibwaresoftsolutions
The items can be printed using print, println, or printf, but print prints every element while keeping the cursor in the same line. The cursor is moved to the next line via println. Additionally, we can use format identifiers with printf.
| Is This Answer Correct ? | 0 Yes | 0 No |
The items can be printed using print, println, or printf, but print prints every element while keeping the cursor in the same line. The cursor is moved to the next line via println. Additionally, we can use format identifiers with printf.
| Is This Answer Correct ? | 0 Yes | 0 No |
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public class AboutStrings{ public static void main(String args[]){ String s1="hello"; String s2="hel"; String s3="lo"; String s4=s2+s3; //to know the hash codes of s1,s4. System.out.println(s1.hashCode()); System.out.println(s4.hashCode()); // these two s1 and s4 are having same hashcodes. if(s1==s4){ System.out.println("s1 and s4 are same."); }else System.out.println("s1 and s4 are not same."); } } Somebody told me that, == operator compares references of the objects. In the above example even though s1 and s4 are refering to same object(having same hash codes), it is printing s1 and s4 are not same. Can anybody explain in detail why it is behaving like this? Thanks in Advance RavuriVinod
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