What will i and j equal after the code below is executed? Explain your answer.
After the above code executes, i will equal 6, but j will equal 5. Understanding the reason for this is fundamental to understanding how the unary increment ( ++ ) and decrement ( -- ) operators work in C++.
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In inline " expression passed as argument are evalauated once " while in macro "in some cases expression passed as argument are evaluated more than once " --> i am not getting it plz help to make me understand....
0 Answers College School Exams Tests, CS,
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