solve (x-1)(x-9)=8;

Answers were Sorted based on User's Feedback



solve (x-1)(x-9)=8;..

Answer / sravan

(x-1)(x-9)=8;
x^2-10x+1=0
x=-b(+ or -)sqrt(b^2-4ac)/2a

Answer x=5+2*sqrt(6)

Is This Answer Correct ?    2 Yes 1 No

solve (x-1)(x-9)=8;..

Answer / jatinder verma

(x-1)(x-9)=8

x^2-9x-x+9=8

x^2-10x+9=8

x^2-10x+9-8=0

x^2-10x+1=0

x^2+1=10x

x*x+1=10x

x+1=10x/x

x+1=10

x=10-1

x=9

Is This Answer Correct ?    1 Yes 6 No

solve (x-1)(x-9)=8;..

Answer / mani

x=1/8

Is This Answer Correct ?    0 Yes 6 No

Post New Answer

More Core Java Interview Questions

What are methods and how are they defined?

0 Answers  


How do you execute a thread in java?

0 Answers  


What is map java?

0 Answers  


What an i/o filter?

0 Answers  


What is a boolean structure?

0 Answers  






why we r not use pointers in corejava?

2 Answers   Samsung,


solve this is my problem byte a=40,byte b=50 both add value is 90 this is with in range of byte... byte range is -128to 127.... why this pgm gives error like type mismatch.... package javapgms; public class byte1 { public static void main(String args[]) { byte a=40,b=50; byte c=a+b; System.out.println(c); } } note : dont use int k... a,b,c are in byte range... mind it..

2 Answers  


Explain the term virtual machine?

0 Answers   Adobe,


What is jit compiler ?

0 Answers  


What is unicode?

1 Answers  


When we can access the static data member without creating the object what is the need of the object in java.

5 Answers   Airhub, ssinformatics,


what is the full form of java

3 Answers  


Categories