Answer / Suresh.d

In C++, you cannot directly swap objects of different classes without using a third variable or a function. Here's an example demonstrating how to use a function for swapping:

```cpp
#include <iostream>
using namespace std;

class A {
public:
int data;
A(int data) : data(data) {}
};

class B {
public:
char name[10];
B(char *name) : str(name) {}
const char* getName() { return str; }
private:
char str[10];
};

void swap(A &a, A &b) {
A temp = a;
a = b;
b = temp;
}

void swap(B &a, B &b) {
char *temp = a.getName();
a.str = b.getName();
b.str = temp;
}

int main() {
A a1(10);
A a2(20);
B b1("John");
B b2("Doe");

cout << "a1 data: " << a1.data << "n";
cout << "a2 data: " << a2.data << "n";
cout << "b1 name: " << b1.getName() << "n";
cout << "b2 name: " << b2.getName() << "n";

swap(a1, a2);
swap(b1, b2);

cout << "After swapping:n";
cout << "a1 data: " << a1.data << "n";
cout << "a2 data: " << a2.data << "n";
cout << "b1 name: " << b1.getName() << "n";
cout << "b2 name: " << b2.getName() << "n";

return 0;
}

assume the program must insert 4 elements from the key board and then do the following programs.sequential search(search one of the elements),using insertion sort(sort the element) and using selection sort(sort the element).

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