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if a ball is dropped from 8 meter and it bounce back half
the distance then what is the distance it travel before
going to rest?
- 8 Answers
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Answer / nishanth
to reach land
first time it travels 8 mtrs
next time (half=4) 4+4 mtrs (up&down)
next time (half=4) 2+2 mtrs (up&down)
next time (half=4) 1+1 mtrs (up&down)
and so on.
Altogether,close to 24 mtrs.
| Is This Answer Correct ? | 20 Yes | 2 No |
Answer / sabarish
Land to ground from air : 8
first bounce from ground to air back : 8/2
first bounce from air to ground: 8/2
for second and viceverse : 8/4 + 8/4
..... 8/8 + 8/8 + 8/16+ 8/16...
adding altogether we get approx 24m
| Is This Answer Correct ? | 10 Yes | 0 No |
Answer / arun a k
8up+4up+4down+2up+2down+1up+1down+1/2up+1/2down+1/4up+1/4dow
n+..................
Almost 24
| Is This Answer Correct ? | 9 Yes | 0 No |
8+8(.5)*2+8(.5)^2*2+8(.5)^3*2...
8+2(8(.5)+8(.5)^2+8(.5)^3...)
Infinity= u1/1-r
u1=8(.5). r=.5
8+2(8(.5)/1-5)
8+2*8
24
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / v venu gopal
8 + 8/2 + 8/4 + 8/8 + ..... 8(1+ 1/2 + 1/4 + ...) a GP of
infinite sum.... formula is ... a / (1-r)...
so,a = 1 and r = 1/2;
ans : 16
| Is This Answer Correct ? | 5 Yes | 8 No |
Answer / suganya
Ball dropped frm 8 meter,
Half the distance=1/2(8)
=4
Total distanc travelled= 8+4+4
=16 meter
| Is This Answer Correct ? | 0 Yes | 10 No |
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