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How to read 2 positions at a time in a data area? I have
created a data area of length and i have to read the values
of the data area like 91-92,93-94 at a time up till 100
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Answer / chandrababu
Please see below code
Ex TESTDTA value: ABCDEFGHIJKL
0001.00 PGM
0002.00 DCL VAR(&AB) TYPE(*CHAR) LEN(2)
0002.01 DCL VAR(&I) TYPE(*DEC) LEN(2) VALUE(1)
0003.00 READ: IF COND(&I *LE 24) THEN(DO)
0004.00 RTVDTAARA DTAARA(DURGA4001/TESTDTA (&I 2)) RTNVAR(&AB)
0004.01 CHGVAR VAR(&I) VALUE(&I +2)
0004.02 IF COND(&AB *NE ' ') THEN(DO)
0004.03 SNDUSRMSG MSG(&AB)
0004.04 ENDDO
0004.05 ELSE CMD(GOTO CMDLBL(END))
0006.00 GOTO READ
0007.00 ENDDO
0008.00 END:
0009.00 ENDPGM
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / chandrababu
To read two digits from data area we co as below
TESTDTA data area value is ABCDEFGHIJKL
Program:
0001.00 PGM
0002.00 DCL VAR(&AB) TYPE(*CHAR) LEN(2)
0002.01 DCL VAR(&I) TYPE(*DEC) LEN(2) VALUE(1)
0003.00 READ: IF COND(&I *LE 24) THEN(DO)
0004.00 RTVDTAARA DTAARA(DURGA4001/TESTDTA (&I 2)) RTNVAR(&AB)
0004.01 CHGVAR VAR(&I) VALUE(&I +2)
0004.02 IF COND(&AB *NE ' ') THEN(DO)
0004.03 SNDUSRMSG MSG(&AB)
0004.04 ENDDO
0004.05 ELSE CMD(GOTO CMDLBL(END))
0006.00 GOTO READ
0007.00 ENDDO
0008.00 END:
0009.00 ENDPGM
| Is This Answer Correct ? | 1 Yes | 0 No |
You can achieve the above by a CL Program. I'm writing a
sample program which is reading DATA AREA 'TESTDTA' of
length 6.
PGM
DCL VAR(&A) TYPE(*CHAR) STG(*AUTO) LEN(1)
DCL VAR(&B) TYPE(*CHAR) STG(*AUTO) LEN(1)
DCL VAR(&C) TYPE(*CHAR) STG(*AUTO) LEN(1)
DCL VAR(&D) TYPE(*CHAR) STG(*AUTO) LEN(1)
DCL VAR(&E) TYPE(*CHAR) STG(*AUTO) LEN(1)
DCL VAR(&F) TYPE(*CHAR) STG(*AUTO) LEN(1)
RTVDTAARA DTAARA(ICIWRKPUS/TESTDTA (1 1)) RTNVAR(&A)
RTVDTAARA DTAARA(ICIWRKPUS/TESTDTA (2 1)) RTNVAR(&B)
RTVDTAARA DTAARA(ICIWRKPUS/TESTDTA (3 1)) RTNVAR(&C)
RTVDTAARA DTAARA(ICIWRKPUS/TESTDTA (4 1)) RTNVAR(&D)
RTVDTAARA DTAARA(ICIWRKPUS/TESTDTA (5 1)) RTNVAR(&E)
RTVDTAARA DTAARA(ICIWRKPUS/TESTDTA (6 1)) RTNVAR(&F)
SNDUSRMSG MSG(&A)
SNDUSRMSG MSG(&B)
SNDUSRMSG MSG(&C)
SNDUSRMSG MSG(&D)
SNDUSRMSG MSG(&E)
SNDUSRMSG MSG(&F)
ENDPGM
| Is This Answer Correct ? | 3 Yes | 3 No |
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