Answer / Bhupinder Kaur

In Object-Oriented Programming (OOPS), you can create multiple sorting algorithms for a single class. Here's an example in Java using interfaces and a generic SortableList class:

1. Create an interface Sortable with the compare() method:

```
public interface Sortable<T> {
int compare(T o1, T o2);
}
```
2. Create a generic SortableList class implementing Comparable and Comparator interfaces:

```
import java.util.*;

public class SortableList<T extends Sortable<?>> implements List<T> {
private ArrayList<T> list = new ArrayList<>();

public void add(T element) {
list.add(element);
}

@Override
public int compareTo(SortableList<?> o) {
if (o == null || !(o instanceof SortableList)) return -1;
Collections.sort(this, new Comparator<T>() {
@Override
public int compare(T t1, T t2) {
return t1.compare(t2, t1);
}
});
Collections.sort((SortableList<?>) o, new Comparator<T>() {
@Override
public int compare(T t1, T t2) {
return t1.compare(t2, t1);
}
});
return this.size() - o.size();
}

// Implement other List methods here...
}
```
3. Create a custom class implementing the Sortable interface and define the compare() method to use different sorting algorithms:

```
public class MyNumber implements Sortable<MyNumber> {
private int number;

public MyNumber(int number) {
this.number = number;
}

@Override
public int compare(MyNumber o1, MyNumber o2) {
// sort by absolute value for example:
return Math.abs(o1.number) - Math.abs(o2.number);
}
}
```
4. Now you can create a SortableList and add sorted numbers to it:

```
SortableList<MyNumber> list = new SortableList<>();
list.add(new MyNumber(-5));
list.add(new MyNumber(3));
list.add(new MyNumber(-7));
list.add(new MyNumber(2));
// list is now sorted by absolute value: [-7, -5, 2, 3]
```

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