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Given a triangle ABC, how would you use only a compass and
straight edge to find a point P such that triangles ABP, ACP
and BCP have equal perimeters? (Assume that ABC is
constructed so that a solution does exist.)
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Answer Posted / vasudev
take a equilateral 3angle.... place compass pt @ each vertices.. draw an arc... mark d pt wr all arcs meet.. thats d pt P ..... thus it gives 3angle of equal perimeter
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