if int1 has the value 12, int has the value 18, and int3 has
the value 21, what is the result:
int1 < int2 && int2 < int 3
Answers were Sorted based on User's Feedback
Answer / arikuntha varathan
since 12<18 and also 18<21 the codition becomes true
| Is This Answer Correct ? | 13 Yes | 1 No |
Answer / murad shaikh
here int1=12
int2=18 (int=18, is given as int2)
int3=21
so
int1 < int2 && int2 < int3
12 < 18 && 18 < 21
ans = 21;
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / tarun
int1 = 12
int = 18 (not int 2)
int 3 = 21
then 1nt1 <int2, int2 value is not known
also int2< int3 , int2 value is not known
| Is This Answer Correct ? | 0 Yes | 3 No |
Find out the bug in this code,because of that this code will not compile....... #include <iostream> #include <new> #include <cstring> using namespace std; class balance { double cur_bal; char name[80]; public: balance(double n, char *s) { cur_bal = n; strcpy(name, s); } ~balance() { cout << "Destructing "; cout << name << "\n"; } void set(double n, char *s) { cur_bal = n; strcpy(name, s); } void get_bal(double &n, char *s) { n = cur_bal; strcpy(s, name); } }; int main() { balance *p; char s[80]; double n; int i; try { p = new balance [3]; // allocate entire array } catch (bad_alloc xa) { cout << "Allocation Failure\n"; return 1; }
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