write a c++ program that gives output
4
3 4
2 3 4
1 2 3 4 using looping statement
Answers were Sorted based on User's Feedback
Answer / rajesh
4
3 4
2 3 4
1 2 3 4
#include<stdio.h>
int main()
{
int i, j, n=4;
for(i=n; i>=1; i--)
{
for(j=i; j<=n; j++)
{
printf("%d",j);
}
printf("\n");
}
printf("\n");
}
| Is This Answer Correct ? | 32 Yes | 1 No |
Answer / rajesh
This answer is to print :
4342341234
#include<stdio.h>
int main()
{
int i, space, num, n=4;
for(i=1; i<=n; i++)
{
for(space=1; space<=n-i; space++)
{
}
for(num=space; num<=n; num++)
{
printf("%d",num);
}
}
printf("\n");
}
| Is This Answer Correct ? | 13 Yes | 3 No |
Answer / sandeep mannnarakkal
void printSeries(int nNum)
{
for ( int i = 0 ; i < nNum ; i ++)
{
for ( int j = nNum -i ; j <= nNum ; j ++)
{
cout << j;
}
cout << endl;
}
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / rajesh
This answer is to print :
4
34
234
1234
#include<stdio.h>
int main()
{
int i, space, num, n=4;
for(i=1; i<=n; i++)
{
for(space=1; space<=n-i; space++)
{
printf(" ");
}
for(num=space; num<=n; num++)
{
printf("%d",num);
}
printf("\n");
}
printf("\n");
}
| Is This Answer Correct ? | 2 Yes | 9 No |
this is to swap to strings....but in output the whole strings are swapped leaving first as it is...why it is so #include<iostream.h> int main() { char a[]="ajeet"; char b[]="singh"; long x=*a; long y=*b; cout<<x<<":"<<y; x=x+y; y=x-y; x=x-y; *a=x; *b=y; cout<<x<<":"<<y; cout<<&a<<endl; cout<<&b<<endl; }
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