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4 years ago father was 9 times older than his son. after 2
years father was 42.what is the present age of his son and
father.
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Answer / indu
son's present age s 8,
if d fathers age is 42 after 2 yrs..then 4yrs before
he must be 36(4*9).
so that time d son's age s 4 and now 8.
| Is This Answer Correct ? | 13 Yes | 4 No |
Answer / skumarcpr8
let present father & son age is X and Y
from Question after 2 years father age is X+2
X+2=42
X=42-2=40..............(1)
agin,
from Question ago 4years father age is (X-4) & son age is (Y-4)
X-4=9(Y-4)
or X-4=9y-36
or X-9y=-36+4
or 40-9y=-32 [from eq. (1) x=40]
or -9y=-32-40
or y=-72/-9
or y=8
so present father age is 40 & present son age is 8 years
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / angu ganesh
According to the question,
2 years after Father's age is 42.
So Present age of Father is 40 years explicitly.
4 years ago Father's age is 36. In this stage Father's age
is 9 times older than his Son. (ie) Father's age is equal
to 10 times of his Son's age.
10(Son's age) = Father's age
10x=36 => x=3.6 (ie) Four years ago, Son's
age is 3.6. Present age of son is 7.6 years
Answer. Father's age is 40 years.
Son's age is 7.6 years (7 years)
| Is This Answer Correct ? | 0 Yes | 1 No |
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