how to get the second max val for every group in a table
Answers were Sorted based on User's Feedback
Answer / venkat
select * from (
select e.deptno,d.dname,e.sal,dense_rank() over (
partition by e.deptno
order by e.sal desc ) "RANK",
e.ename
from emp_test e,dept_test d
where e.deptno=d.deptno)
where rank=2
| Is This Answer Correct ? | 9 Yes | 5 No |
Answer / suman rana
--venkat u r almost correct, since u have used "" (double
quotes) so column name will be come case sensitive.
select * from (
select e.deptno,d.dname,e.sal,dense_rank() over (
partition by e.deptno
order by e.sal desc ) RANK, e.ename
from emp_test e,dept_test d where e.deptno=d.deptno)
where rank=2
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / suman rana
select * from emp e where 2 = ( select count(distinct sal)
from emp e1 where e1.deptno = e.deptno and E.SAL <= E1.SAL)
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ram posam
select * from (select deptno,sal,rank() over(partition by
deptno order by sal desc) k
from emp
group by deptno,sal)
where k=&n;
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / indu
select max(sal) from salary where sal NOT IN (select max(sal) from salary)
| Is This Answer Correct ? | 9 Yes | 13 No |
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