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Write a simple program to find the size of different basic
data types in C.
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Answer / rajiv
int x,y,b;
char a;
x=sizeof(y);
b=sizeof(a);
printf("the size of int is %d & the size of char is
%d",x,b);
| Is This Answer Correct ? | 20 Yes | 4 No |
Answer / jugad
#include
#include
int main()
{
printf(“%d %d %d %d”,sizeof(int),sizeof(unsigned
int),sizeof(float),sizeof(char));
getch();
return 0;
}
courtesy:http://answerwale.co.cc/?p=23
| Is This Answer Correct ? | 21 Yes | 7 No |
Answer / gajendra patil
#include <stdio.h>
#include <conio.h>
int main(){
int *a;
printf("\nSIZE OF DIFFERENT DATA TYPES\n");
printf("\n------------------------------");
printf("\n\tBASIC");
printf("\n------------------------------");
printf("\nCHARACTER \t: %d byte(s)",sizeof(char));
printf("\nSHORT \t\t: %d byte(s)",sizeof(short));
printf("\nINTEGER \t: %d byte(s)",sizeof(int));
printf("\nLONG \t\t: %d byte(s)",sizeof(long));
printf("\nFLOAT \t\t: %d byte(s)",sizeof(float));
printf("\nDOUBLE \t\t: %d byte(s)",sizeof(double));
printf("\nLONG DOUBLE \t: %d byte(s)",sizeof(long double));
printf("\nLONG LONG \t: %d byte(s)",sizeof(long long));
printf("\nPOINTER (any) \t: %d byte(s)",sizeof(*a));
printf("\nARRAY \t\t: sizeOfDataType * sizeOfArray [eg. int a[10]=%d byte(s)]",sizeof(int)*10);
printf("\n------------------------------");
return 0;
}
| Is This Answer Correct ? | 5 Yes | 2 No |
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